This topic explains how to work with date values in VBScript and gives examples of date operations. It contains the following sections:
Objects and Functions for Working With Date Values
Getting Tomorrow’s and Yesterday’s Dates
Calculating the Year and Month Duration
Basics
When writing scripts we often deal with dates. There are certain date value formats and TestComplete routines that help handle dates.
Since the TestComplete scripting engine only supports OLEcompatible data types, the datetime values are implemented as floatingpoint variant values in a special format. The integer part of this value represents the number of days that have passed since December 30, 1899. The number after the decimal separator represents the fraction of a 24hour period that has elapsed. However, you do not have to understand what these floatingpoint values represent. TestComplete provides several routines that help you convert these values to their string representation (see below).
Below are some examples of datetime values and their meaning:
Value  Meaning 

0.25  December 30, 1899. 6:00 AM 
36345.5  July 4, 1999. 12:00 PM 
39094.65625  January 12, 2007. 3:45 PM 
When you are only working with date values the fractional part can be omitted.
Objects and Functions for Working With Date Values
TestComplete has the aqDateTime
object that contains methods that can be useful when operating with dates.
Method  Description 

AddDays  Adds or subtracts the specified number of days to (from) the given date. 
AddMonths  Adds or subtracts the specified number of months to (from) the given date. 
AddTime  Adds or subtracts the specified number of days, hours, minutes and seconds to (from) the given date. 
Compare  Compares two specified date/time values. 
GetDay  Returns the ordinal number of a day in a month. 
GetDayOfWeek  Returns the day of the week for the specified date. 
GetDayOfYear  Returns the ordinal number of a day in a year. 
GetMonth  Returns the month number of the specified date. 
GetYear  Returns the year number of the specified date. 
IsLeapYear  Indicates whether the specified year is a leap year. 
Now  Returns the current date and time. 
SetDateElements  Returns the Date variable having the specified year, month and day. 
SetDateTimeElements  Returns the Date variable having the specified date and time portions. 
SetSystemDateTime  Assigns the specified date and time as the system date and time. 
Today  Returns the current date. 
One more object, aqConvert
, provides methods to convert strings between date values and their string equivalents:
Method  Description 

DateTimeToFormatStr  Converts the given date value to a string using the specified format. 
DateTimeToStr  Converts the given date value to a string. 
StrToDate  Converts the specified string to a date value. 
StrToDateTime  Converts the specified string to a date/time value. 
The aqDateTime
and aqConvert
objects are available for all supported scripting languages, so that you can use them to operate with date values regardless of the chosen language.
You can also use these and other builtin VBScript functions in your scripts. Here is a list of builtin functions that can be useful when dealing with dates:
Function  Description 

CDate  Returns an expression that has been converted to a Variant of subtype Date 
Date  Returns the current system date. (See a note below to learn about the format of date values in VBScript.) 
DateAdd  Returns the date to which the specified time interval has been added. 
DateDiff  Returns the number of intervals between two dates. 
DatePart  Returns the specified part of a given date. 
DateSerial  Returns a Variant of subtype Date for the specified year, month, and day. 
DateValue  Returns a Variant of subtype Date. 
Day  Returns a whole number between 1 and 31, inclusive, representing the day of the month. 
FormatDateTime  Returns an expression formatted as a date or time. 
IsDate  Returns a Boolean value indicating whether an expression can be converted to a date. 
Month  Returns a whole number between 1 and 12, inclusive, representing the month of the year. 
MonthName  Returns a string indicating the specified month. 
Now  Returns the current date and time according to the date and time set on your computer. 
Weekday  Returns a whole number representing the day of the week. 
WeekdayName  Returns a string indicating the specified day of the week. 
Year  Returns a whole number representing the year. 
Note:  Native VBScript date/time values are stored as strings in the #MM/DD/YYYY HH:MM:SS PM/AM# format. (For example, #1/25/2005 2:17:38 PM#.) These strings are automatically converted to the floatingpoint variant format when required. In most cases, you can pass a VBScript date to a TestComplete routine or vice versa and get the correct results. However, the initial representation of VBScript date/time values should be kept in mind. 
Getting Current Date
There are two routines that return current date: Today
and Now
. The difference between them is that the value returned by the Now
routine includes both the date and time parts, whereas the Date
routine returns only the date part. The script below demonstrates how to use them.
VBScript
Sub GetDate
Dim TodayValue, NowValue, StringTodayValue, StringNowValue, VariantTodayValue, VariantNowValue
' Obtain the current date
TodayValue = aqDateTime.Today
' Obtain the current date and time
NowValue = aqDateTime.Now
' Convert the returned date/time values to the string values
StringTodayValue = aqConvert.DateTimeToStr(TodayValue)
StringNowValue = aqConvert.DateTimeToStr(NowValue)
' Post the converted values to the log
Log.Message("The date obtained from the Today routine is " + StringTodayValue)
Log.Message("The date obtained from the Now routine is " + StringNowValue)
' Convert the floatingpoint values to the string values
VariantTodayValue = aqConvert.FloatToStr(TodayValue)
VariantNowValue = aqConvert.FloatToStr(NowValue)
' Post the converted values to the log
Log.Message("The variant representation of TodayValue is " + VariantTodayValue)
Log.Message("The variant representation of NowValue is " + VariantNowValue)
End Sub
Getting Tomorrow’s and Yesterday’s Dates
The samples below demonstrate how the aqDateTime
object can be used to calculate
tomorrow's date.
The current date is obtained via the aqDateTime.Today
method. Then the current date value is incremented via the aqDateTime.AddDays
method.
The DateTimeToStr
method of the aqConvert
object is used to convert the date value to a string that is posted to the TestComplete log.
VBScript
Function TomorrowDate
' Obtain the current date
CurrentDate = aqDateTime.Today
' Convert the date/time value to a string and post it to the log
Today = aqConvert.DateTimeToStr(CurrentDate)
Log.Message("Today is " + Today)
' Calculate the tomorrow’s date, convert the returned date to a string and post this string to the log
TomorrowDate = aqDateTime.AddDays(CurrentDate, 1)
ConvertedTomorrowDate = aqConvert.DateTimeToStr(TomorrowDate)
Log.Message("Tomorrow will be " + ConvertedTomorrowDate)
End Function
In a similar way you can calculate any date that differs from the current day by a certain number of days: yesterday, the next or previous week and so on. For example to get yesterday’s date, you have to pass the 1 value to the aqDateTime.AddDays
method as the second (Days) parameter.
VBScript
Function YesterdayDate
' Obtain the current date
CurrentDate = aqDateTime.Today
' Convert the date/time value to a string and post it to the log
Today = aqConvert.DateTimeToStr(CurrentDate)
Log.Message("Today is " + Today)
' Calculate the yesterday’s date, convert the returned date to a string and post this string to the log
YesterdayDate = aqDateTime.AddDays(CurrentDate, 1)
ConvertedYesterdayDate = aqConvert.DateTimeToStr(YesterdayDate)
Log.Message("Yesterday was " + ConvertedYesterdayDate)
End Function
Comparing Dates
To compare date/time values, use the aqDateTime.Compare
method rather than comparison operators (like =, >, <, <> and others) provided by the scripting engine:
Calculating the Year and Month Duration
Generally there are 365 days in a calendar year. However the length of an astronomical year is about 365.242375 days, so in the course of time the fractional part would result in an extra day and the calendar year would lag from the astronomical. To avoid this the leap year that is 366 days long was invented.
The Gregorian calendar is the current standard calendar in most of the world and it adds a 29th day to February in all years evenly divisible by 4, except for centennial years (those ending in 00), which only receive the extra day if they are evenly divisible by 400. The aqDateTime
object has a special method ,IsLeapYear
, that accepts the year number and returns true if the specified year is a leap year. We can use this method to get the exact number of days in the desired year:
VBScript
Function DaysInYear(YearNo)
If aqDateTime.IsLeapYear(YearNo) Then DaysInYear=366 Else DaysInYear=365
End Function
Using the IsLeapYear
method we can get the number of days in the month. For all months, except February, the duration of a month is fixed and is either 30 or 31 days. The duration of February is 28 or 29 days depending on whether the current year is a leap year or not. The routine that gets the month duration would be the following:
Encoding and Decoding Date Values
Since date values are represented as variants, special routines are required that convert a variant value to a calendar date format and backwards. These operations are performed by the SetDateElements, GetYear, GetMonth and GetDay methods of the aqDateTime
object. These methods take into account whether the current year is a leap year and the number of days in a month to guarantee that the value is valid. SetDateElements
accepts the parts of a date and returns a variant date value.
VBScript
Sub EncodeDateDemo
' Create a Date variable having the specified year, month and day values
myDate=aqDateTime.SetDateElements(2005,12,25)
' Convert the value of the myDate variable to a string using the specified format and post this string to the log
EncodedDate = aqConvert.DateTimeToFormatStr(myDate,"%B/%#d/%Y")
Log.Message("The encoded date is "+ EncodedDate)
' Convert the value of the myDate variable to a variant value and post it to the log
VariantDate = aqConvert.IntToStr(myDate)
Log.Message("The variant representation of it is "+ VariantDate)
End Sub
The GetYear
, GetMonth
and GetDay
methods perform a contrary operation: they accept a variant date/time value and return respective date parts of that value. Here is an example of how to use these routines:
VBScript
Sub DecodeDateDemo
Dim Year, Month, Day
' Obtain the current date
CurrentDate=aqDateTime.Today
' Return the parts of the current date value and then post them to the log
Year=aqDateTime.GetYear(CurrentDate)
Month=aqDateTime.GetMonth(CurrentDate)
Day=aqDateTime.GetDay(CurrentDate)
Log.Message(aqConvert.IntToStr(Day)+" day(s) have passed since the beginning of the "+aqConvert.IntToStr(Month)+" month of "+aqConvert.IntToStr(Year)+" year.")
End Sub
Modifying Date Values
Despite the fact that date/time values are represented as floatingpoint numbers, you cannot explicitly use ordinary arithmetic operators to change dates or time. However, the aqDateTime
scripting object provides a number of methods that were designed to modify date/time values. These methods are: AddMonths
, AddDays
and AddTime
. The AddTime
method allows you to modify date and time portions at once.
As it is said above, these methods are used both for incrementing and decrementing date/time values. If a positive number is passed as Month, Days or as another parameter, the resulting value is increased. If the parameter is negative, the resulting value is decreased.
These methods take into account the number of days in the month, whether the year is a leap year and other aspects of time calculations, that is why the resulting value is guaranteed to be valid.
The code below demonstrates how to use these methods:
VBScript
Sub ModifyDates
Dim Date, AlteredDate
Date=aqDateTime.SetDateElements(2007,1,25)
' Increase the date by 7 days
'Note the month change
AlteredDate=aqDateTime.AddDays(Date,7)
Log.Message("Initial date: "+aqConvert.DateTimeToStr(Date))
Log.Message("Altered date 1: "+aqConvert.DateTimeToStr(AlteredDate))
' Increase the date by one month
' Note that 28 days were added, since the month in AlteredDate is February
AlteredDate=aqDateTime.AddMonths(AlteredDate,1)
Log.Message("Altered date 2: "+aqConvert.DateTimeToStr(AlteredDate))
' Decrease the date by 1 day
AlteredDate=aqDateTime.AddTime(AlteredDate,1,0,0,0)
Log.Message("Altered date 3: "+aqConvert.DateTimeToStr(AlteredDate))
End Sub
Dealing with Week Days
Besides recognizing the date, month and year, you may need to know which day of the week a certain date is. The aqDateTime.GetDayOfWeek
method can help you do this. It accepts a variant date and returns the number of the week day that corresponds to it. The returned number ranges from 1 to 7, where 1 corresponds to Sunday, 2  to Monday, and so on. The sample code below obtains the current date, calculates the day of the week and posts the name of the day to the log.
VBScript
Sub DayOfWeekDemo
Dim WeekDay, DayName
WeekDay=aqDateTime.GetDayOfWeek(aqDateTime.Today)
Select Case WeekDay
Case 1: DayName="Sunday"
Case 2: DayName="Monday"
Case 3: DayName="Tuesday"
Case 4: DayName="Wednesday"
Case 5: DayName="Thursday"
Case 6: DayName="Friday"
Case 7: DayName="Saturday"
End Select
Log.Message("Today is "+DayName)
End Sub
Note: 
The GetDayOfWeek method uses the United States system of week notation where a week starts on Sunday and ends on Saturday. However, the ISO 8601 “Data elements and interchange formats  Information interchange  Representation of dates and times” standard recommends another system of week notation. In this system, a week starts on Monday and ends on Sunday. To convert a US week day number to the ISO 8601 format, you can use the following routine:
The result of this function is also an integer number, but 1 corresponds to Monday, 2 to Tuesday and so on.

In addition to the day of the week, we can find out the week boundaries that the specified date belongs, that is, calculate the dates that the week starts and ends. This could be done using the following two routines. Here the number of a week day is subtracted from the specified date to get the beginning of a week, and to get the end of the week, six days are added to the calculated date.
VBScript
Function StartOfWeek (InputDate)
' Truncate the input parameter
InputDate=Fix(InputDate)
' Using a US week day number
StartOfWeek=aqDateTime.AddDays(InputDate,  aqDateTime.GetDayOfWeek(InputDate) + 1)
' Using an ISO week day number
' StartOfWeek=aqDateTime.AddDays(InputDate,  ISODayOfWeek(InputDate) + 1)
End Function
Function EndOfWeek (InputDate)
' Truncate the input parameter
InputDate=Fix(InputDate)
' Using a US week day number
EndOfWeek=aqDateTime.AddDays(InputDate,  aqDateTime.GetDayOfWeek(InputDate) + 7)
' Using an ISO week day number
' EndOfWeek=aqDateTime.AddDays(InputDate,  ISODayOfWeek(InputDate) + 7)
End Function
Note: 
Since the routines use the aqDateTime.GetDayOfWeek method, which returns a US week day number, the dates returned by the routines are Sunday and Saturday, correspondingly. To apply the ISO 8601 week day notation, you should use the last code line where the aqDateTime.GetDayOfWeek call is replaced with a call to the ISODayOfWeek function (the code of the ISODayOfWeek function is provided in the note above). In this case, the first routine will return the date that falls on Monday and the second one will return the date that falls on Sunday. 
Another frequent operation when dealing with dates is calculating the number of weeks that have passed since the beginning of the year. First we should clarify what week should be considered as the first week of a year. According to the ISO 8601 standard, the first week of a year is a week with the majority (four or more) of days in the starting year. In our case it is better to use another equivalent definition of the first week: the week with the date, January, 4th.
Here is the routine that calculates the week number in compliance with this rule. It accepts the date that belongs to the desired week, determines the end of this week and the end of the week that includes January 4, and that calculates the week number as the difference between those two values divided by 7.
VBScript
Function WeekNumber(InputDate)
' Truncate the input parameter
InputDate=Fix(InputDate)
YearNo=aqDateTime.GetYear(InputDate)
EndOfFirstWeek=EndOfWeek(aqDateTime.SetDateElements(YearNo,1,4))
EndOfCurrentWeek=EndOfWeek(InputDate)
WeekNumber= 1+(aqDateTime.GetDayOfYear(EndOfCurrentWeek)aqDateTime.GetDayOfYear(EndOfFirstWeek))/7
End Function
Sometimes it is useful to know what day of the week the desired month starts or ends. The routines below return the week day number that correspond to the beginning and end of the month. They only have one input parameter that specifies the date which belongs to the desired month. If the parameter is missing then the routines return the results for the current month. The routines are similar to calculating the beginning and end of a week, but instead of the week day number, the day of the month number is used.
VBScript
Function StartOfMonthDay (InputDate)
Dim DayNo
DayNo=aqDateTime.GetDay(InputDate)
StartDate = aqDateTime.AddDays(InputDate, DayNo+1)
' Use a US week day number
StartOfMonthDay=aqDateTime.GetDayOfWeek(StartDate)
' Use an ISO week day number
' StartOfMonthDay=ISODayOfWeek(StartDate)
End Function
Function EndOfMonthDay (InputDate)
Dim YearNo, MonthNo, DayNo
DayNo=aqDateTime.GetDay(InputDate)
MonthNo=aqDateTime.GetMonth(InputDate)
YearNo=aqDateTime.GetYear(InputDate)
EndDate = aqDateTime.AddDays(InputDate,  DayNo + DaysInMonth(MonthNo, YearNo))
' Use a US week day number
EndOfMonthDay=aqDateTime.GetDayOfWeek(EndDate)
' Use an ISO week day number
' EndOfMonthDay=ISODayOfWeek(EndDate)
End Function
See Also
Working With Dates
VBScript  Working With Time Values
aqDateTime Object